<PRE><B>Question 188908</B>
Surface area is what they are looking for:
:

Surface Area of Pyramid = s² + 2sl = A + 2sl
Volume of Pyramid = (1/3)b²h
:
where s is the side, h height, l slant height
:
slant height:{{{l=sqrt(5^2+12^2)=sqrt(169)=13}}}
:
SA={{{10^2+2(10)(13)=360}}} sq in
:
V=1/3(10)(12)=360 cu in</PRE>