Question 188689
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Let known, <font color=blue>breadth=width=W</font>


Also, <font color=blue>Length = 4dm + W
Area = 192 sq dm</font>


Then, A = L x W = (4 + W)(W) = 192 sq dm
W^2 + 4W -192 = 0
(W+16)(W-12)=0
W=-16dm, discard
<font color=red>W=12 dm</font> = Breadth


Then, L = 4 + 12 = <font color=red>16 dm</font> = Length


Check,
A = L * W
192sq dm= (16)(12)
192sq dm = 192sq dm


Thank you,
Jojo</font>