Question 188879
Let x = width of the parking lot
   2x + 200 = length of the parking lot (being 200 yards more than twice the width)

The area of the rectangular lot is the length*width

so 

{{{x*(2x+200)=40000}}}

simplifying...

{{{2x^2+200x=40000}}}

divide both sides by 2 to simplify

{{{x^2+100x=20000}}}

{{{x^2+100x-20000}}}

factoring...

{{{(x+500)*(x-400)=0}}}

possible solutions are x=-500 and x=400. We take x=400 yards as length cannot be negative

so the width of the parking lot is 400 yards and the length is 1000 yards