Question 188875
    how much pure acid should be mix with 2 gallonsof 40% acid solution in order to get a 70%acid solution. can you please show me how to do it my self, thanks
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Let x = amount of pure (100%) acid added
then
"amt of acid added" + "amt of acid of original mix" = "70% of total mixture"
x + .40(2) = .70(x+2)
x + .80 = .70x + 1.40
.30x + .80 = 1.40
.30x = .60
x = .60/.30
x = 2 gallons