Question 188800
How do I solve the follwoing system of equations? 
y ={{{ sqrt (x) }}}  + 4
y = 2x + 1 
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There's more than one way, but since both right sides = y, I'd set them equal to each other.
2x+1 = sqrt(x) + 4
sqrt(x) = 2x-3
x = 4x^2 - 12x + 9
4x^2 - 13x - 9 = 0
*[invoke solve_quadratic_equation 4,-13,-9]