Question 184957
The sum of two numbers is 6 less than twice the first number.
Their difference is 10 less than four times the second number.
<br>first number = x
second number = y
<br>x+y=2x-6     this equals
y=x-6
<br>x-y=4y-10    this equals
x=5y-10
<br>substitute the second equation into the first equation
x=5y-10 --> y=x-6
y=5y-10-6    (simplify)
y=5y-16    (subtract 5y)
-4y=-16   (divide by -4)
y=4
<br>substitute back into second equation
x=5y-10
x=5(4)-10
x=20-10
x=10
<br><b><big><big>x=10 y=4<big><big><b>