Question 188558
-8y^3-10y^2-3y=0
-y(8y^2+10y+3)=0
-y(4y+3)(2y+1)=0
-y=0
y=0 ans.
4y+3=0
4y=-3
y=-3/4 ans.
2y+1=0
2y=-1
y=-1/2 ans.