Question 188599
{{{8x=(y^2-2y+1)-1-15}}}
:
{{{8x=(y-1)^2-16}}}
:
{{{x=1/8(y-1)^2-2}}}
:
vertex is at (-2,1)
:
1/4p=1/8--->4p=8-->p=2
:
focus is at (0,1) and directrix is x=-4
:
distance across parabola at focus is 4p  4(2)=8
:
{{{graph(300,300,-10,10,-10,10,sqrt(8x+16)+1)}}}