Question 26206
THese are already in slope-intercept form, so you ould graph them;
eq.1;
y-intercept=-1
slope = {{{2/1}}}
eq.2;
y-intercepr=1
slope = {{{1/1}}}
So on the graph you will make a your first point at (0,-1)
From that point you will go up 2 units and to the right 1;
Your next point should be (1,1);
Then from there go up 2 units and right 1;
3rd point (2,3);
Eq.2;
You will start at point (0,1);
Fom that point go up 1 unit and to th right 1, your second point should be (1,2);
From that point go up 1 unit and to the right, 3rd point (2,3), lets do  1 more point;
so from point (2,3) go up 1 unit and to the right 1 (3,4)
Where those lines intersect, that point will be the solution for both eq.
{{{graph (300,300, -3,4,-3,4, (2/1)x-1, x+1)}}}
Hope you understand
=)