<PRE><B>Question 188486</B>
How many liters of a 20% alcohol solution and how many liters of a 50% alcohol solution must be mixed to produce 9 liters of a 30% alcohol solution?
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Equation:
alcohol + alcohol = alcohol
0.20x + 0.50(9-x) = 0.30*9
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20x + 50*9 - 50x = 30*9
-30x = -20*9
x = 6 (amt. of 20% solution in the mix)
9-x = 3 (amt of 50% solution in the mix)
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Cheers,
Stan H.
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