Question 188337
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If 87% of As are Bs, then 13% of As are NOT Bs.  (100% - 87% = 13%).  If 13% of As are not Bs, and there are 13 As that are not Bs:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  .13A = 13\ \ \Rightarrow\ \ A = \frac{13}{.13} \ \ \Rightarrow\ \ A = 100]


Therefore, there are 0.87 times 100 = 87 As that are Bs.  And if .03Bs are As, then:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  .03B = 87 \ \ \Rightarrow\ \ B = \frac{87}{.03} \ \ \Rightarrow\ \ B = 2900]


Since 3% of Bs are As, 97% of Bs are NOT As, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ .97B = .97(2900) = 2813]




John
*[tex \LARGE e^{i\pi} + 1 = 0]
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