<PRE><B>Question 188363</B>
QUESTION:
(6x^2-5x-4)/(3x^2+kx+20) = (2x+1)/(x-5)
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(2x+1)(3x-4)/(3x^2+kx+20) = (2x+1)/(x-5)
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Divide both sides by (2x+1) to get:
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(3x-4)/(3x^2+kx+20) = 1/(x-5)

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Cross-multiply to get:
(3x-4)(x-5) = 3x^2+kx+20
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3x^2 -19x + 20 = 3x^2 + kx + 20
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-19x = kx
--
k = -19
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Cheers,
Stan H.</PRE>