<PRE><B>Question 188286</B>
One of the many trig identities is {{{sin(A+B)=sin(A)cos(B)+cos(A)sin(B)}}}




*[Tex \LARGE F = \frac{.6W sin(\theta + 90)}{sin(12)}] ... Start with the given equation.



*[Tex \LARGE F = \frac{.6W (sin(\theta)cos(90)+cos(\theta)sin(90))}{sin(12)}] ... Use the identity given above



*[Tex \LARGE F = \frac{.6W (sin(\theta)(0)+cos(\theta)(1))}{sin(12)}] ... Evaluate the cosine of 90 degrees to get 0. Evaluate the sine of 90 degrees to get 1. 



*[Tex \LARGE F = \frac{.6W ( 0 + cos(\theta) )}{sin(12)}] ... Multiply



*[Tex \LARGE F = \frac{.6W cos(\theta)}{sin(12)}] ... Simplify



*[Tex \LARGE F = \frac{.6W cos(\theta)}{0.2079}] ... Evaluate the sine of 12 degrees to get approximately 0.2079



*[Tex \LARGE F = 2.8858W cos(\theta)] ... Divide {{{0.6/0.2079}}} to get roughly 2.8858



*[Tex \LARGE F = 2.9W cos(\theta)] ... Round to the nearest tenth</PRE>