Question 188241
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 5x-7y=35]


You are almost correct.  A <i>y</i>-intercept is in the form (0,<i>b</i>), so you substitute 0 for <i>x</i> and solve for <i>y</i>:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 5(0)-7y=35 \ \ \Rightarrow\ \ y = -5 \text{ when }\LARGE x = 0 ]


and the intercept is (0,-5).  You did this part correctly.


An <i>x</i>-intercept is in the form (<i>a</i>,0), so you substitute 0 for <i>y</i> and solve for <i>x</i>:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 5x-7(0)=35 \ \ \Rightarrow\ \ x = 7 \text{ when }\LARGE y = 0 ]


and the intercept is (7,0).  Here, you have the coordinates reversed.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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