Question 188148
Since (x-4) is a factor, this means that x=4 is a root (or zero) of {{{x^3+x^2-14x-24}}}


Now set up a synthetic division table by placing the zero 4 and the coefficients of {{{x^3+x^2-14x-24}}} along the top row. Perform synthetic division to get:

<pre>

 4 |1   1   -14   -24
   |    4    20    24
   -------------------
    1   5     6     0


</pre>



Since the remainder is 0, this means that 4 is a root.



The first three numbers in the bottom row form the quadratic: {{{x^2+5x+6}}}



Now solve {{{x^2+5x+6=0}}} to find the other 2 solutions.