Question 187953
{{{(4-i)*(-2+6i)}}} Start with the given expression.



{{{(4)(-2)+(4)(6i)+(-i)(-2)+(-i)(6i)}}} FOIL.



{{{-8+24i+2i-6i^2}}} Multiply.



{{{-8+24i+2i-6(-1)}}} Replace {{{i^2}}} with {{{-1}}}. Note: {{{i^2=-1}}}.



{{{-8+24i+2i+6}}} Multiply.



{{{-2+26i}}} Combine like terms.



So {{{(4-i)*(-2+6i)=-2+26i}}}.



So the expression is now in standard form {{{a+bi}}} where {{{a=-2}}} and {{{b=26}}}