Question 187899
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Let <font color=red>x</font>=Ken's Age
So, <font color=red>x+3</font>= Brenda's Age


Condition: Ken's Age x Brenda's Age = 180
(x)(x+3)=180
x^2+3x-180=0
(x+15)(x-12)=0
x=-15, discard & <font color=red>x=12</font>, Ken's Age
3+12=<font color=red>15</font>, Brenda's Age


Thank you,
Jojo</font>