<PRE><B>Question 187844</B>
i need help on this problem. i am supposed to solve the equation and check for extraneous solutions. i worked it out but i did not get the right answer. i need help finding the real one. 

3^(x^2)=1
log3(x^2)=log1
x^2log3=log1
x^2=log1/log3
x^2=0
x= square root of 0
x=0
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check the answer.
(3^(x^2)) + 5 = 6
3^0 + 5 = 6
1 + 5 = 6
6 = 6  Must be right.

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