Question 187790
"The sum of the digits of a three-digit number is 11." ---> h+t+u=11 



"If the digits are reversed, the new number is 46 more than 5 times the old number" ---> 100u+10t+h=5(100h+10t+u)+46 



"If the hundreds digit plus twice the tens digit is equal to the units digit" ---> h+2t=u



So solve system below to find number:


*[Tex \LARGE \left\{\begin{array}{l}h+t+u=11 \\ \\ 100u+10t+h=5(100h+10t+u)+46 \\ \\ h+2t=u\end{array}\right.]



Post back if you can't solve.



Ans: original number is 137