Question 187695


OK. LET'S SEE.  I'LL DO IT AND THEN WE'LL COMPARE.
(y-7)/(y^2-16) + (7-y)/(16-y^2) 
Cross multiplying, we get:
(y-7)(16-y^2)=-y^3+7y^2+16y-112
(7-y)(y^2-16)=-y^3+7y^2+16y-112
Now for the denominator:
(y^2-16)(16-y^2)=-y^4+32y^2-256
I THINK THIS IS WHERE YOU MAY HAVE GOTTEN OFF TRACK

Now, putting the numerator and denominator together, we have:
{Notice, I'm factoring a -2 out of the numerator and a -1 out of the denominator}
-2(y^3-7y^2-16y+112)/-1(y^4-32y+256) and this equals
2((y-7)(y^2-16))/(y^2-16)^2 cancel out the (y^2-16) and we get
2(y-7)/(y^2-16)------------------I think this is the answer

Look at the second term;  if we factor out -1 from the numerator and denominator, what do we get?
(y-7)/(y^2-16)+(-1)(y-7)/(-1)(y^2-16)) Whoaaaa!! the -1's cancel and we now have:

y-7)/(y^2-16)+(y-7)/(y^2-16)) =2(y-7)/(y^2-16)

Maybe an easier way??? 

Hope this helps, Kattie---ptaylor