Question 187680
I'm assuming that you mean that you graphed the function {{{g(x)=x^2}}} on the interval *[Tex \LARGE \left(-\infty,0\right)]. If so, then you have the correct graph.


Yes you are right. The first function would have a closed circle at the point (0,0) while the function {{{g(x)=x^2}}} would have an open circle.


By the way, the graph should look like this


<img src="http://i150.photobucket.com/albums/s91/jim_thompson5910/Algebra%20dot%20com/graph-2.png">