Question 187674
3x^2 + 3y^2 - 6x - 6 = 0 (describe and sketch the given equation) 
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Divide thru by 3 to get:
x^2 + y^2 - 2x - 2 = 0
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x^2 - 2x + ? + y^2 = 2

x^2 - 2x + 1 + y^2 = 3

(x-1)^2 + (y-0)^2 = 3
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Circle with center at (1,0) and radius = sqrt(3)
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Cheers,
Stan H.