Question 187655
f(x)=(x+5)(x^2+7)-(x+5)(6x+2)


f(x)=(x+5)[(x^2+7)-(6x+2)]



f(x)=(x+5)(x^2+7-6x-2)



f(x)=(x+5)(x^2-6x+5)



f(x)=(x+5)(x-5)(x-1)


0=(x+5)(x-5)(x-1)



x+5=0, x-5=0, or x-1=0


Roots: x=-5, x=5, or x=1