Question 187623
Do you mean {{{x^2-32=0}}} ???




{{{x^2-32=0}}} Start with the given equation.



{{{x^2=0+32}}} Add {{{32}}} to both sides.



{{{x^2=32}}} Combine like terms.



{{{x=0+-sqrt(32)}}} Take the square root of both sides.



{{{x=sqrt(32)}}} or {{{x=-sqrt(32)}}} Break up the "plus/minus" to form two equations.



{{{x=4*sqrt(2)}}} or {{{x=-4*sqrt(2)}}}  Simplify the square root.



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Answer:



So the solutions are {{{x=4*sqrt(2)}}} or {{{x=-4*sqrt(2)}}}.