Question 187622
I'm assuming you mean {{{sqrt(75a^2)/sqrt(3)}}}



{{{sqrt(75a^2)/sqrt(3)=sqrt((75a^2)/3)=sqrt(25a^2)=sqrt(25)*sqrt(a^2)=5a}}} where {{{a>=0}}} (ie "a" is NOT negative)



So {{{sqrt(75a^2)/sqrt(3)=5a}}} where {{{a>=0}}} (ie "a" is NOT negative)