<PRE><B>Question 187525</B>
Let the length and width be l and w respectively
Perimeter = 2( l + w ) = 62		(1)
Also given  2(l + 21 + 2w ) = 120	(2)
Ie  2(l + w) + 2(21 + w) = 120
62 + 42 + 2w = 120
104 + 2w = 120
2w = 16, so w = 8
Plugging in the value  of w in eqn(1)
2(l + 8) = 62
2l + 16 = 62
2l = 62 – 16 =  46 so l = 46/2 = 23 
Ans:  Length = 23 meters and Width = 8 meters


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