Question 187604
64x^6+y^6


(4x^2)^3+(y^2)^3


(4x^2+y^2)( (4x^2)^2 - (4x^2)(y^2) + (y^2)^2 )


(4x^2+y^2)( 16x^4 - 4x^2y^2 + y^4 )



Ans: 

64x^6+y^6 factors to (4x^2+y^2)(16x^4-4x^2y^2+y^4)