Question 187610
 Find the roots of the polynomial function.
y=x^3+8
y=x^3+8=(x+2)(x^2-2x+4)
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x+2=0 or x^2-2x+4 = 0
x = -2 or Use the quadratic Formula:
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x = [2 +- sqrt(4-4*1*4)]/2
x = [2 +- sqrt(-12)]/2
x = [2 +- 2isqrt(3)]/2
x = [1 +- isqrt(3)
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Cheers,
Stan H.