<PRE><B>Question 187578</B>
What is the distance traveled by a ball thrown downward at a velocity of 12 feet per second if the ball falls for 6 seconds? 
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Using 32 ft/sec/sec as acceleration due to gravity:
v = 32*6 + 12 feet/sec at impact.
v = 204 ft/sec
The average speed is (12 + 204)/2 = 108 ft/sec
108*6 = 648 feet.
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Had the ball just been released with no initial downward speed, the distance would be 16t^2 = 576 feet.
576 + 6*12 = 648 feet also.</PRE>