Question 187577
Please perform the operation of the following complex number. The answer should be in a + bi form: i(2+i)(3-2i) 
I am an older student who has been out of highschool for 27 years. I tried the foil method of the 2 sets of parentheses, then applied the outer i, but my answer was incorrect. Thank you. 
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i(2+i)(3-2i)  Multiply thru by the i
=(2i-1)*(3-2i)
=6i+4 -3+2i
=1+8i