<PRE><B>Question 187449</B>
{{{f(x)=x^3-3x^2-5x+7}}} Start with the given equation.



{{{f(-2)=(-2)^3-3(-2)^2-5(-2)+7}}} Plug in {{{x=-2}}}.



{{{f(-2)=1(-8)-3(-2)^2-5(-2)+7}}} Cube {{{-2}}} to get {{{-8}}}.



{{{f(-2)=1(-8)-3(4)-5(-2)+7}}} Square {{{-2}}} to get {{{4}}}.



{{{f(-2)=-8-3(4)-5(-2)+7}}} Multiply {{{1}}} and {{{-8}}} to get {{{-8}}}.



{{{f(-2)=-8-12-5(-2)+7}}} Multiply {{{-3}}} and {{{4}}} to get {{{-12}}}.



{{{f(-2)=-8-12+10+7}}} Multiply {{{-5}}} and {{{-2}}} to get {{{10}}}.



{{{f(-2)=-3}}} Combine like terms.</PRE>