Question 187398
a mini-TV screen has a diagonal of 6.5 inches. the length of the screen is 3.5 inches longer than the width. what are the actual dimensions of the screen.
now with this I thought I would try and use the Pothagorean therom. which would be a squared + b squared = c squared. so far i have gotten that 6.5 squared is 42.25
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That's a part of it.
w is the width, so the length is w+3.5 (usually TVs are width and height, but whatever)
{{{w^2 + (w+3.5)^2 = 42.25}}}  Pythagorean theorem
{{{w^2 + w^2 + 7w + 12.25 = 42.25}}}
{{{2w^2 + 7w - 30 = 0}}}
*[invoke solve_quadratic_equation 2,7,-30]
w = -6, 2.5  Ignore the -6
w = 2.5, length = 6