<PRE><B>Question 187309</B>
Let put Number of Nickel = N
        Number of Dime   = D
        Number of Quarter= Q

and we know : D= 2N ; Q= 2D

Therefore we can establish the equation as follows:

N*5 + D*10 +Q*25 = 1250    ( notice: $12.50 = 1250 cents)

D/2 *5 + D*10 + 2D*25 =1250

5D + 20D + 100D  = 2500    ( result is by multiplying the equation to 2) 

          125D = 2500
             D = 20 dimes


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