Question 187336

For slope intercept form, we have to manipulate the terms such that only y has to come on the left side. Like y = mx+b
But you got 2y on the left side and not y.  Even for that you made a mistake while rearranging the terms. Let us see how we do it
The original equation was  2x – 2y = 6 . The first step is to remove the 2x from the left side. This can be done by subtracting 2x on both sides
2x – 2y – 2x =  - 2x +6
That gives  - 2y = - 2x +6 . To isolate y on the left side we have to divide both sides by – 2
-	2y /(- 2) =  (- 2x + 6) / -2
That is  y  = (-2/-2) x + (6/-2)  means y = x – 3 which is the equation in slope intercept form. When we rewrite the equation in slope intercept form, The coefficient of x term (m) will be the slope and the last number (b) will be its y intercept. Here  the coefficient =1. Similarly the last number ( ie. y intercept) is -3

So your answer is: Slope intercept form is y = x – 3,  slope =1 and  y intercept – 3
Your teacher drew the graph through (-1, 4), (1, -2) because the line passes through these points. Let us verify that
Eqn is  y = x – 3 . Put x = -1 then y = - 1 – 3 = - 4 so (-1, -4 ) is a point on it.
Similarly put x = 1, y = x – 3 = 1 – 3 = - 2  so ( 1, - 2) also lies on it.



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