Question 187308
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A 30-60-90 right triangle has sides in proportion:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  \frac{1}{2}:\frac{sqrt{3}}{2}:1]


So if the base is the side opposite the 30 angle, then the height is the other leg and is:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{20\,sqrt{3}}{2}]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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