<PRE><B>Question 187276</B>
Let us number these equations
x+y=6		Eqn(1)
x+3y=10		Eqn(2)
Subtracting Eqn(1) from Eqn(2) we get
2y = 4 Dividing both sides by 2 we get 2y/2 = 4/2 , so y = 2
Plugging in the value of y in Eqn(1) we get x + 2 = 6
Subtracting 2 from both sides we have x = 4

So the answer is x = 4 and y = 2


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