<PRE><B>Question 187252</B>
&lt;font face=&quot;Times New Roman&quot; size=&quot;+2&quot;&gt;


A number:  &lt;i&gt;x&lt;/i&gt;


Five times a number: 5&lt;i&gt;x&lt;/i&gt;


Four less than five times a number: 5&lt;i&gt;x&lt;/i&gt; - 4


Is: &quot;=&quot;


Another number: &lt;i&gt;y&lt;/i&gt;


Twelve more than another number:  &lt;i&gt;y&lt;/i&gt; + 12


So:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 5x - 4 = y + 12]


The first number: &lt;i&gt;x&lt;/i&gt;


Three times the first number:  3&lt;i&gt;x&lt;/i&gt;


The second number: &lt;i&gt;y&lt;/i&gt;


Twice the second number:  2&lt;i&gt;y&lt;/i&gt;


Three times the first number &lt;i&gt;&lt;b&gt;less&lt;/b&gt;&lt;/i&gt; the second number: 3&lt;i&gt;x&lt;/i&gt; - 2&lt;i&gt;y&lt;/i&gt;


Is eight:  = 8


So:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3x - 2y = 8]


Solve the two-variable, two-equation linear system:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 5x - 4 = y + 12]
*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3x - 2y = 8]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
&lt;/font&gt;</PRE>