Question 187154
{{{(3a^2b)(2a^3b^2)(-ab^4)}}} Start with the given expression.



{{{(3*2(-1))(a^2*a^3*a)(b*b^2*b^4)}}} Rearrange the terms.



{{{-6(a^2*a^3*a)(b*b^2*b^4)}}} Multiply 3, 2, and -1 to get -6



{{{-6(a^(2+3+1))(b^(1+2+4))}}} Add the exponents to multiply the monomials.



{{{-6a^6*b^7}}} Add



So {{{(3a^2b)(2a^3b^2)(-ab^4)=-6a^6*b^7}}}