Question 187166
log(2x^2+3x) = log(10x+30)
2x^3 + 3x = 10x +30
2x^3 – 7x – 30 = 0
(2x+5)(x – 6) = 0
So x = 6 or   – (5/2)




If you still require further clarifications please write to udayakumar.t.r@gmail.com