Question 187166
log(2x^2+3x) = log(10x+30)


2x^2+3x = 10x+30


2x^2+3x - 10x - 30 = 0


2x^2-7x-30 = 0


(x-6)(2x+5) = 0


x-6=0 or 2x+5=0


Ans: x=6 or x=-5/2