Question 187156
{{{3^(4x-7) = 1/9}}}
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We notice that {{{9}}} can be written as {{{3^2}}}
So we have 

{{{3^(4x-7) = 1/(3^2)}}}

Now {{{1/(3^2)}}} can be written as {{{3^(-2)}}}
So we have

{{{3^(4x-7) = 3^(-2)}}}

Now we can equate the exponents because the bases
are equal, positive, and {{{""<>1}}}.
So we have

{{{4x-7=-2}}}
{{{4x=5}}}
{{{x=5/4}}}

Edwin</pre>