Question 187102
A quadratic looks like:
y = ax^2 + bx + c
.
The problem gives you three points:
(1,-2),(2,-2),(3,-4) 
Which relates to:
(1,-2)
-2 = a(1)^2 + b(1) + c
-2 = a + b + c
.
(2,-2)
-2 = a(2)^2 + b(2) + c
-2 = 4a + 2b + c
.
(3,-4) 
-4 = a(3)^2 + b(3) + c
-4 = 9a + 3b + c
.
Now, you have basically a "system of equations":
-2 = a + b + c
-2 = 4a + 2b + c
-4 = 9a + 3b + c
.
Can you finish the problem from here?