<PRE><B>Question 187040</B>
*[Tex \LARGE \left(64\right)^{-\frac{2}{3}}] ... Start with the given expression.



*[Tex \LARGE \frac{1}{\left(64\right)^{\frac{2}{3}}}] ... Flip the fraction to make the exponent positive



*[Tex \LARGE \frac{1}{\left(\sqrt[3]{64}\right)^2}] Convert to radical notation



*[Tex \LARGE \frac{1}{\left(4\right)^2}] Take the cube root of 64 to get 4. Note: {{{4^3=64}}} which tells us that {{{root(3,64)=4}}}



*[Tex \LARGE \frac{1}{16}] Square 4 to get 16



So *[Tex \LARGE \left(64\right)^{-\frac{2}{3}}=\frac{1}{16}]</PRE>