Question 186994
2y^ 2 -6y= 3
2y^2 -6y -3 = 0
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Use quadratic equation:
y = [6 +- sqrt(36 - 4*2*-3)]/4

y = [6 +- sqrt(60)]/4

y = [6 +- 2sqrt(15)]/4

y = [3 +- sqrt(15)]/2
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Cheers,
Stan H.