Question 186950
"x varies directly as the square of y and inversely as z" translates to {{{x=ky^2/z}}} (let me know if you need help with the translation)




{{{x=ky^2/z}}} Start with the given equation.



{{{112=k(6)^2/3}}} Plug in y=6, z=3 and x=112



{{{112(3)=k(6)^2}}} Multiply both sides by 3.



{{{336=k(6)^2}}} Multiply



{{{336=k(36)}}} Square 6 to get 36



{{{336/36=k}}} Divide both sides by 36 to isolate 'k'.



{{{28/3=k}}} Reduce



So the constant is {{{k=28/3}}}



-------------------------------



So the equation is:



{{{x=((28/3)y^2)/z}}} 



{{{x=((28/3)(3)^2)/(3)}}} Plug in {{{k=28/3}}},  y=3 and z=3



{{{x=((28/3)(9))/(3)}}} Square 3 to get 9



{{{x=28}}} Multiply and reduce