Question 186847
{{{(-6+2i)(7-i)(4+3i)}}} Start with the given expression.



{{{(-42+20i-2i^2)(4+3i)}}} FOIL the first two binomials



{{{(-42+20i-2(-1))(4+3i)}}} Replace {{{i^2}}} with -1



{{{(-42+20i+2)(4+3i)}}} Multiply



{{{(-40+20i)(4+3i)}}} Combine like terms.



{{{-160-40i+60i^2}}} FOIL



{{{-160-40i+60(-1)}}} Replace {{{i^2}}} with -1



{{{-160-40i-60}}} Multiply



{{{-220-40i}}} Combine like terms.



So {{{(-6+2i)(7-i)(4+3i)=-220-40i}}}