Question 186840
The perimeter of a rectangle = 2( l +w)
Here l = w+3, pluging in that we get p = 2( w+3 + w) = 2(2w+3)

The given condition is p >= 51
That is   2(2w + 3) ≥ 51
4w + 6 ≥ 51   adding – 6 on both sides we get
4w ≥ 51- 6
4w ≥ 45
Dividing both sides by 4 we get
w ≥ 45/4

w≥  11.25 . So the width must be at least 11.25 meters


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