Question 186829
{{{2/(z+3)}}} + {{{4/(5z)}}}
The common denominator will be 5z(z+3), then you have:
{{{(2(5z) + 4(x+3))/(5z(z+3))}}} = {{{(10z + 4z + 12)/(5z(z+3))}}} = {{{(14z + 12)/(5z(z+3))}}} ={{{(2(7z + 6))/(5z(z+3))}}}