Question 186721
Let x be one number. The x+2 is the next higher odd one
{{{x^2 + (x+2)^2 = 394}}}
{{{x^2 + x^2 + 4x + 4 = 394}}}
{{{2x^2 + 4x - 390 = 0}}}
{{{2(x-13)(x+15)= 0}}}
so x = 13 or -15
answer are 13,15  and -15,-13