Question 186706
Remember, all quadratics are of the form {{{y=ax^2+bx+c}}}


So when they say that they want the values of 'a', 'b' and 'c' to be integers, they just want them to be whole numbers. So we could say that {{{a=1}}}, {{{b=2}}}, and {{{c=7}}} to get {{{y=x^2+2x+7}}}



For rational values, just substitute in fractions for 'a', 'b' and 'c'


Finally, for irrational values, just plug in non perfect square roots such as {{{sqrt(2)}}}, {{{sqrt(5)}}} and {{{sqrt(11)}}} into 'a', 'b' and 'c'